A 3-digit number is such that it is equal to 19 times the sum of its digits. What is its largest possible value among the given answers?
Select An Answer
A
114
B
133
C
152
D
399
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&19(a + b+ c)\\100a + 10b + c &=&19 a + 19b + 19c\\(100-19)a + (10-19)b +(1-19)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-19)a + (10-19)b}{(1-19)}\end{equation} for the statement to be true. Among all the true answers, select the largest.
\begin{array}{rcl}100a + 10b + c &=&19(a + b+ c)\\100a + 10b + c &=&19 a + 19b + 19c\\(100-19)a + (10-19)b +(1-19)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-19)a + (10-19)b}{(1-19)}\end{equation} for the statement to be true. Among all the true answers, select the largest.
A Televison set was sold for a 3-digit price. The price is 19 times of the sum of all the 3 digits. What is the largest possible price?
\begin{array}{rcl}100a + 10b + c &=&19(a + b+ c)\\100a + 10b + c &=&19 a + 19b + 19c\\(100-19)a + (10-19)b +(1-19)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-19)a + (10-19)b}{(19-1)}\end{equation} for the statement to be true.
Among all the true answers, select the largest.
A primary school has a 3-digit number of students. The Number of students is 19 times the sum of all its digits. What is its $smallest$ possible value among all the possible answers?
Select An Answer
A
399
B
285
C
266
D
247
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&19(a + b+ c)\\100a + 10b + c &=&19 a + 19b + 19c\\(100-19)a + (10-19)b +(1-19)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-19)a + (10-19)b}{(19-1)}\end{equation} for the statement to be true.
Among all the true answers, select the smallest.
\begin{array}{rcl}100a + 10b + c &=&19(a + b+ c)\\100a + 10b + c &=&19 a + 19b + 19c\\(100-19)a + (10-19)b +(1-19)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-19)a + (10-19)b}{(19-1)}\end{equation} for the statement to be true.
Among all the true answers, select the smallest.
In a birthday party Charles bought 3-digit number of sweets to share with all his friends. The sum of all the 3-digits is exactly $\frac{1}{28}$ of the number of sweets. What the $largest$ possible number of sweets does Charles have?
Select An Answer
A
588
B
476
C
448
D
392
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&28(a + b+ c)\\100a + 10b + c &=&28 a + 28b + 28c\\(100-28)a + (10-28)b +(1-28)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-28)a + (10-28)b}{(28-1)}\end{equation} for the statement to be true.
Among all the true answers, select the largest.
\begin{array}{rcl}100a + 10b + c &=&28(a + b+ c)\\100a + 10b + c &=&28 a + 28b + 28c\\(100-28)a + (10-28)b +(1-28)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-28)a + (10-28)b}{(28-1)}\end{equation} for the statement to be true.
Among all the true answers, select the largest.
I bought my computer at a price of 3-digit number. The price is equal to 28 times the sum of its digits. What is its $smallest$ possible value among the given answers?
Select An Answer
A
588
B
476
C
448
D
392
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&28(a + b+ c)\\100a + 10b + c &=&28 a + 28b + 28c\\(100-28)a + (10-28)b +(1-28)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-28)a + (10-28)b}{(28-1)}\end{equation} for the statement to be true. Among all the true answers, select the smallest.
\begin{array}{rcl}100a + 10b + c &=&28(a + b+ c)\\100a + 10b + c &=&28 a + 28b + 28c\\(100-28)a + (10-28)b +(1-28)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-28)a + (10-28)b}{(28-1)}\end{equation} for the statement to be true. Among all the true answers, select the smallest.
A hotel has many rooms. The number of rooms is 37 times the sum of its digits. The hotel has a 3 digit number of rooms. What is its smallest possible number of rooms among the given answers?
Select An Answer
A
999
B
888
C
777
D
666
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&37(a + b+ c)\\100a + 10b + c &=&37 a + 37b + 37c\\(100-37)a + (10-37)b +(1-37)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-37)a + (10-37)b}{(37-1)}\end{equation} for the statement to be true. Among all the true answers, select the smallest.
\begin{array}{rcl}100a + 10b + c &=&37(a + b+ c)\\100a + 10b + c &=&37 a + 37b + 37c\\(100-37)a + (10-37)b +(1-37)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-37)a + (10-37)b}{(37-1)}\end{equation} for the statement to be true. Among all the true answers, select the smallest.
Mike bought an Air-conditioner at a 3-digit price. The sum of the 3-digits is only $\frac{1}{37}$ of the price. What is its largest possible value among the given answers?
Select An Answer
A
999
B
888
C
777
D
666
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&37(a + b+ c)\\100a + 10b + c &=&37 a + 37b + 37c\\(100-37)a + (10-37)b +(1-37)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-37)a + (10-37)b}{(37-1)}\end{equation} for the statement to be true. Among all the true answers, select the largest.
\begin{array}{rcl}100a + 10b + c &=&37(a + b+ c)\\100a + 10b + c &=&37 a + 37b + 37c\\(100-37)a + (10-37)b +(1-37)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-37)a + (10-37)b}{(37-1)}\end{equation} for the statement to be true. Among all the true answers, select the largest.
A 3-digit number is such that it is equal to 46 times the sum of its digits. What is its largest possible value among the given answers?
Select An Answer
A
966
B
874
C
828
D
782
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&46(a + b+ c)\\100a + 10b + c &=&46 a + 46b + 46c\\(100-46)a + (10-46)b +(1-46)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-46)a + (10-46)b}{(46-1)}\end{equation} for the statement to be true. Among all the true answers, select the largest.
\begin{array}{rcl}100a + 10b + c &=&46(a + b+ c)\\100a + 10b + c &=&46 a + 46b + 46c\\(100-46)a + (10-46)b +(1-46)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-46)a + (10-46)b}{(46-1)}\end{equation} for the statement to be true. Among all the true answers, select the largest.
My new jacket costs 3-digit number of price, which is equal to 46 times the sum of its digits. What is its smallest possible value among the given answers?
Select An Answer
A
966
B
874
C
828
D
782
Sorry. Please check the correct answer below.
\begin{array}{rcl}100a + 10b + c &=&46(a + b+ c)\\100a + 10b + c &=&46 a + 46b + 46c\\(100-46)a + (10-46)b +(1-46)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-46)a + (10-46)b}{(46-1)}\end{equation} for the statement to be true. Among all the true answers, select the smallest.
\begin{array}{rcl}100a + 10b + c &=&46(a + b+ c)\\100a + 10b + c &=&46 a + 46b + 46c\\(100-46)a + (10-46)b +(1-46)c &=& 0 \end{array} Fill in any given a and b, c must be: \begin{equation}c = \frac{(100-46)a + (10-46)b}{(46-1)}\end{equation} for the statement to be true. Among all the true answers, select the smallest.